Решение на Първа задача от Йоана Тодорова
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Резултати
- 4 точки от тестове
- 0 бонус точки
- 4 точки общо
- 5 успешни тест(а)
- 3 неуспешни тест(а)
Код
Лог от изпълнението
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Failures:
1) Integer#prime_divisors works with negative numbers
Failure/Error: (-10).prime_divisors.should eq [2, 5]
Math::DomainError:
Numerical argument is out of domain - "sqrt"
# /tmp/d20130307-6960-qejq1o/solution.rb:3:in `sqrt'
# /tmp/d20130307-6960-qejq1o/solution.rb:3:in `prime_num?'
# /tmp/d20130307-6960-qejq1o/solution.rb:17:in `prime_divisors'
# /tmp/d20130307-6960-qejq1o/spec.rb:11:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
2) Range#fizzbuzz it works with the first 100 numbers
Failure/Error: (1..100).fizzbuzz.should eq [
expected: [1, 2, :fizz, 4, :buzz, :fizz, 7, 8, :fizz, :buzz, 11, :fizz, 13, 14, :fizzbuzz, 16, 17, :fizz, 19, :buzz, :fizz, 22, 23, :fizz, :buzz, 26, :fizz, 28, 29, :fizzbuzz, 31, 32, :fizz, 34, :buzz, :fizz, 37, 38, :fizz, :buzz, 41, :fizz, 43, 44, :fizzbuzz, 46, 47, :fizz, 49, :buzz, :fizz, 52, 53, :fizz, :buzz, 56, :fizz, 58, 59, :fizzbuzz, 61, 62, :fizz, 64, :buzz, :fizz, 67, 68, :fizz, :buzz, 71, :fizz, 73, 74, :fizzbuzz, 76, 77, :fizz, 79, :buzz, :fizz, 82, 83, :fizz, :buzz, 86, :fizz, 88, 89, :fizzbuzz, 91, 92, :fizz, 94, :buzz, :fizz, 97, 98, :fizz, :buzz]
got: [1, 2, :fizz, 4, :buzz, :fizz, 7, 8, :fizz, :buzz, 11, :fizz, 13, 14, :fizz, 16, 17, :fizz, 19, :buzz, :fizz, 22, 23, :fizz, :buzz, 26, :fizz, 28, 29, :fizz, 31, 32, :fizz, 34, :buzz, :fizz, 37, 38, :fizz, :buzz, 41, :fizz, 43, 44, :fizz, 46, 47, :fizz, 49, :buzz, :fizz, 52, 53, :fizz, :buzz, 56, :fizz, 58, 59, :fizz, 61, 62, :fizz, 64, :buzz, :fizz, 67, 68, :fizz, :buzz, 71, :fizz, 73, 74, :fizz, 76, 77, :fizz, 79, :buzz, :fizz, 82, 83, :fizz, :buzz, 86, :fizz, 88, 89, :fizz, 91, 92, :fizz, 94, :buzz, :fizz, 97, 98, :fizz, :buzz]
(compared using ==)
# /tmp/d20130307-6960-qejq1o/spec.rb:18:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
3) Range#fizzbuzz works with tricky ranges
Failure/Error: (10...17).fizzbuzz.should eq [:buzz, 11, :fizz, 13, 14, :fizzbuzz, 16]
expected: [:buzz, 11, :fizz, 13, 14, :fizzbuzz, 16]
got: [:buzz, 11, :fizz, 13, 14, :fizz, 16]
(compared using ==)
# /tmp/d20130307-6960-qejq1o/spec.rb:33:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
Finished in 0.00947 seconds
8 examples, 3 failures
Failed examples:
rspec /tmp/d20130307-6960-qejq1o/spec.rb:10 # Integer#prime_divisors works with negative numbers
rspec /tmp/d20130307-6960-qejq1o/spec.rb:17 # Range#fizzbuzz it works with the first 100 numbers
rspec /tmp/d20130307-6960-qejq1o/spec.rb:32 # Range#fizzbuzz works with tricky ranges
История (1 версия и 1 коментар)
Йоана обнови решението на 14.10.2012 22:45 (преди над 12 години)
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